Aged 5 to 7 years (Key stage 1, year 1 & 2). SATS in year 2
What affects year 1 and 2 students
From 5 to 7 years (Key stage 1, year 1&2) English SATS in year 2
Reading (word and comprehension), writing (spelling and handwriting)
From 5 to 7 years (Key stage 1, year 1&2) Maths SATS in year 2
Number, place value, add, subtract, multiply, divide, fractions, shape, space and measurement
From 5 to 7 years (Key stage 1, year 1&2) Maths SATS in year 2
Working scientifically, plants, animals, everyday materials and seasonal changes
Learn with Videos for Year 1 and 2
Maths: Learn how to Add, Subtract, Multiply and Divide
Aged 8 to 11 years (Key stage 2, year 3-6) SATS in year 6
What affects year 3 to year 6 students
From 8 to 11 years (Key stage 2, year 3-6) English SATS in year 6
Reading (word and comprehension), writing (spelling and handwriting)
Aged 8 to 11 years (Key stage 2, year 3-6) Maths SATS in year 6
Number, calculations, fractions, measurements, geometry, stats, algebra and ratio
Aged 8 to 11 years (Key stage 2, year 3-6) Science SATS in year 6
Sc1:scientific enquiry, sc2:life processes & living, sc3:materials and their properties, sc4:physical processes
Learn with Videos for Year 3 to 6
Maths: basic operations; English - SPAG
Aged 12 to 14 years (Key stage 3) SATS in year 9
The latest on Key stage 3
Aged 12 to 14 years (Key stage 3) English SATS in year 9
Reading and writing, spoken language, spelling, vocabulary and grammar
Aged 12 to 14 years (Key stage 3) Maths SATS in year 9
Numeracy and mathematical reasoning and problem solving
Aged 12 to 14 years (Key stage 3) Science SATS in year 9
Working scientifically, biology, chemistry,and physics.
Aged 15 to 16 years with GCSE's in year 11
The latest changes to GCSE Maths, Science and English
From aged 14 to 16 years (2 year GCSE, year 10 & 11).
Two year GCSE with exams at the end. Two exam papers: Foundation (up to grade C) or Higher (to A*).
From aged 14 to 16 years (2 year GCSE, year 10 & 11).
Two year GCSE with exams at the end. Two exam papers: Foundation (up to grade C) or Higher (to A*).
From aged 14 to 16 years (2 year GCSE, year 10 & 11)
Two year GCSE with exams at the end. Two exam papers: Foundation (up to grade C) or Higher (to A*).
Yr 12-13 news
What's happening in year 12&13 Maths and Physics
Advanced level, usually taken from ages 16-18 years
Yr12: C1+C2+option. Yr13: C3+C4+option. Options= Mechanics,decision maths,statistics. Exams: end Yr13
Advanced level (OCR), usually taken from ages 16-18 years
Year 12 - mechanics, electrons waves, photons. Year 13 - Newtonian, Fields & particles. Exams at end of year 13
Coding
After school clubs: build websites, mobile applications and games. Summer Coding Camp: 5 days of fun
Web BootCamp: 12 intensive weeks to become a web developer.
The Principles for Imagination
There is a lot of emphasis on using Logic at school especially in the later years, to the detriment of Imagination. As we get older, our imagination dwindles and so we need to actively spend time exercising it.
Fuel is the energy for your imagination
We use the principles of Fuel, Freedom and Flexibility to let your imagination soar again.
Freedom lets your imagination soar by removing blocks
We use the principles of Fuel, Freedom and Flexibility to let your imagination soar again.
Flexibility improves imagination by letting you shift mental gears
We use the principles of Fuel, Freedom and Flexibility to let your imagination soar again.
Not really a test , more of an assessment of how you think.
Brain dominance, idea generator or evaluator, learning style
Year 10/11 maths: Using gradients to find equations of lines
On a graph, parallel lines have the same gradient.
For example, y = 3x + 3 and y = 4 + 3x are parallel because they both have a gradient of 3.
The gradient is the value before the x. The other value is where the graph Crosses the y-axis
Q. What is the equations of the lines shown.
ANS
Top line has a gradient of △y/△x= 4/8 (½)
It is a positive gradient.
It crosses the y-axis at 3 so the equation is y = ½x + 3
The lower line is parallel so has the same gradient, ½.
It crosses the y-axis at –2 so the equation is y = ½x – 2
Perpendicular lines cross at right angles.
In the diagram the lines are perpendicular.
The gradients of these two lines are ½ and –2
Multiply line gradients to test if they are perpendicular.
If the answer is –1 they are perpendicular.
In this case ½ × –2 = –1
So flip the first gradient and change the sign
e.g. 1 and –1 are perpendicular
Q1. Find the equation of the perpendicular line to the line shown, which passes through the point (0, 2).
i.e. Work out the gradient and flip and change the sign to get the perpendicular gradient first
Q2. Find equation of perpendicular line to
y = 4 – ¾x which passes through (0, –3)
Q1. The line given has a gradient of – ⅓
Flip the gradient and change the sign
The perpendicular line has a gradient of 3
It passes through (0, 2)
Eq^{n} of the perpendicular line: y = 3x + 2
Q2. Gradient of perpendicular is 4/3
It passes through (0, –3)
Eq^{n} of line is y = 4/3x –3
To find the gradient of a line draw a right angled triangle, then using the 2 points work out the (difference in y)/(difference in x)
e.g. Find the gradient of the line from (1, 2) to (4, 8)
The difference in y = 8 – 2 = 6
The difference in x = 4 – 1 = 3
Gradient = 6/3 = 2 . Note it is positive.
Q1. Work out the gradient between the two points on the diagram.
(Hint: first find the two co-ordinates,
then work out the difference (△) in x and y and divide the two.
Q2. Work out the equation of the line passing through these points
Give your answer in the form ax + by + c = 0
The points are (–3,–3) and (2, 3)
△ y is 3 – –3 = 6
△ x is 2 – – 3 = 5
Gradient is 6/5. Note it is positive.
Work out equation of line using y = mx+c
At point (2,3), substituting: 3 = 6/5 × 2 + c
So c = 15/5 – 12/5 = 3/5
Equation line is y = 6x/5 + 3/5
or 5y – 6x – 3 = 0
Point A has the coordinates (7,2) and point B has the coordinates (1,6)
Q1. Find the equation of a line AB.
Give your answer in the form ax + by + c = 0
Q2. Find the equation of a line that is perpendicular to AB and passes through (0, 0).
Give your answer in the form ax + by + c = 0
The points are (1, 6) and (7, 2)
△ y is 6 – 2 = 4
△ x is 1 – 7 = –6
Gradient is – ⅔.
Work out equation of line using y = mx+c
At point (1, 6), substituting: 6 = – ⅔ × 1 + c
So c = 20/3
Line equation is y = – 2x/3 + 20/3 or
3y + 2x – 20 = 0
Q2 Perpendicular line has gradient 3/2.
At (0, 0), y= mx+ c is 0 = 0 + c so c is 0
Equation perpendicular is y = 3x/2 or
2y – 3x = 0
A tangent just touches a circle.
We can use a circle theorem to help us find the equation of a tangent.
Circle theorems show that the angle between a tangent and a radius in a circle is 90°
Q. A circle has centre (6, 8).
A tangent touches the circle at (3, 12)
Find the equation of the tangent
The line (radius) from the tangent to the circle centre is perpendicular to the tangent line
Work out the gradient of the radius: –4/3
So the gradient of the tangent is ¾
Use y= mx + c and use substitution to work out c
At point (3, 12); 12 = ¾ × 3 + c
so c = 39/4 and
y = ¾ x + 39/4
A circle C has centre (1, 4)
The point A (4, 13) lies on the circumference of the circle.
Find the equation of the tangent to the circle at A
Line AC has gradient, △y/ △x = 9/3 = 3
So the gradient of the perp. tangent = – ⅓
Use y= mx + c and substitute to find c
At (4, 13); 13 = –⅓ × 4 + c so c = 43/3
So y = – ⅓ x + 43/3 or
3y + x – 43 = 0
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